$3 Craps

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Learn How to Play Craps

Proposition Bet Payoffs

Now for the worst and MOST FUN wagers on the table. Proposition bets. You can memorize this page if you wish, but when it comes to the proposition bets;

'Know the payoffs on bets you're making, and make only bets that you know the payoffs!'

For no other reason, by the time you're finished with this page, you will have a higher appreciation for dealers, because keeping track of proposition bets for eight hours would be a bear.

With some prop bets, I'll be able to provide some shortcuts, on others only memorization will do. So, in no particular order:

C & E

If you're going to place a C & E bet, make it easy on yourself AND the dealers, by placing equal amounts on both the C and E. Given equal amounts for each bet, the formula for payoff is three times the TOTAL C & E bet if craps (2,3,12) is rolled, or seven times the TOTAL C & E bet if 11 is rolled.

Total C & E Bet AmountCraps Payoff (3 x total wagered)Eleven Payoff (7 x total wagered)
$2 (one dollar each C & E)$6$14
$4$12$28

So how do most players figure out the payoff? They do it rather stupidly. If a craps rolled with a $2 C & E bet, they would say craps pays 7 to 1, minus the $1 lost on the eleven portion of the wager, for a total of $6. If the 11 had rolled, they would calculate $1 times 15 to 1, minus the $1 lost for the craps portion of the wager for a total of $14.

The stupid way seems simple enough, right? How about if you parlayed that $2 C & E win on the eleven? You're paid $14 and up with the original $2, for a total of a $16 C & E bet. NOW, what's the payoff if the 11 hits again?

Using the shortcut: $16 x 7 = (10 x 7) + (6 x 7) = $112

or the stupid way: $8 x 15 = (8 x 10) + (8 x 5) = 120 - $8 = $112

How to figure out payoff is up to you, I prefer the shortcut.

2 or 12 / 3 or 11

Individually, these prop bets pay either 15 to 1 or 30 to 1. The fact is, you're gonna have to do some math or some serious memorization:

Amount Wagered

2 or 12 Payoff

Formula = 3 times wager & add a 0

3 or 11 Payoff

Formula = 11/2 times wager & add a 0

$1$30 (3 x 1 = 3 add 0 for 30)$15 (1.5 x 1 = 1.50 add 0 for $15)
$2$60$30
$3$90$45
$4$120$60
$5$150$75

2 and 12 are easy, whereas many people get confused with 3 and 11 when the wagers get larger.

Horn Bets

Horn bet calculations are not too bad. Since there are two different payoff structures (15:1 and 30:1), there are two formulas. Though some casinos will allow you to make horn bets in increments OTHER than $4, I'd recommend keeping to the norm, sticking to increments of $4.

Amount Wagered

2 or 12 Payoff

Formula = 7 times wagered amount - (wagered amount / 4)

3 or 11 Payoff

Formula = 3 times wagered amount

$4$27 (7 x 4) - ($4 / 4)$12 (3 x $4)
$8$54 (7 x 8) - ($8 / 4)$24
$12$81$36
$16$108$48
$20$135$60

You could also remember horn bets this way. If you think of every increment of $4 as a unit on the horn, you could then multiply $27 times the number of units if the 2 or 12 hits or $12 times the number of units if the 3 or 11 hit.

Horn High Bets
If you don't already know what it is, a 'Horn High' bet is a horn bet, with an additional wager on a specific horn number. So a '$5 Horn High Yo' is horn bet with $1 each on 2,12, and 3 and $2 on the eleven. You can also have 'Horn High Ace-Duece', 'Horn High 12' or 'Horn High Aces'. Frankly, I think most people who make Horn High bets haven't the vaguest idea what they're supposed to be paid. If you're in a sawdust joint where there are a lot of break in dealers, you'd better know the payoffs or in all likelihood, you'll be underpaid.

Since there are four possibilities of Horn High Bets, you get four tables:

Horn High Yo

Amount Wagered

If Yo,2 or 12 is rolled
Formula = 5 x wager + amount of # that was rolled

If 3 is rolled
Formula = 2 x wager plus amount on # that rolled

$5Yo = $27 (5 x $5) + ($2 on 11)
12 or 2 = $26 (5 x $5) + ($1 on 2/12)
$11 (2 x $5) + $1 on 3
$10Yo = $54 (5 x $10) + ($4 on 11)
12 or 2 = $52 (5 x $10) + ($2 on 2/12)
$22 (2 x $10) + $2 on 3
$15Yo = $81 (5 x $15) + ($6 on 11)
12 or 2 = $78 (5 x $15) + ($3 on 2/12)
$33 (2 x $15) + $3 on 3
$20Yo = $108 (5 x $20) + ($8 on 11)
12 or 2 = $104 (5 x $20) + ($4 on 2/12)
$44 (2 x $20) + $4 on 3

Beginning to have an appreciation for dealers????

Horn High Ace-Deuce

Amount Wagered

If Ace-Deuce,2 or 12 is rolled
Formula = 5 x wager + amount of # that was rolled

If 11 is rolled
Formula = 2 x wager plus amount on # that rolled

$5Yo = $27 (5 x $5) + ($2 on 11)
12 or 2 = $26 (5 x $5) + ($1 on 2/12)
$11 (2 x $5) + $1 on 3
$10Yo = $54 (5 x $10) + ($4 on 11)
12 or 2 = $52 (5 x $10) + ($2 on 2/12)
$22 (2 x $10) + $2 on 3
$15Yo = $81 (5 x $15) + ($6 on 11)
12 or 2 = $78 (5 x $15) + ($3 on 2/12)
$33 (2 x $15) + $3 on 3
$20Yo = $108 (5 x $20) + ($8 on 11)
12 or 2 = $104 (5 x $20) + ($4 on 2/12)
$44 (2 x $20) + $4 on 3

Horn High Twelve

Amount
Wagered

If 12 is rolled
Formula = 11 x wager + amount

on the 12

If 3 or 11 is rolled
Formula = 2 x wager plus amount

on # that rolled

If aces is rolled
Formula = 5 x wager plus amount on aces

$5$57 (11 x $5) + ($2 on 12)$11 (2 x $5) + $1 on 3/11$26 (5 x $5) + $1 on 2
$10$114 (11 x $10) + ($4 on 12)$22 (2 x $10) + $2 on 3/11$52 (5 x $10) + $2 on 2
$15$171 (11 x $15) + ($6 on 12)$33 (2 x $15) + $3 on 3/11$78 (5 x $15) + $3 on 2
$20$228 (11 x $20) + ($8 on 12)$44 (2 x $20) + $4 on 3/11$104 (5 x $20) + $4 on 2

Horn High Aces

Amount
Wagered

If 2 is rolled
Formula = 11 x wager + amount on the 2

If 3 or 11 is rolled
Formula = 2 x wager plus amount

on # that rolled

If 12 is rolled
Formula = 5 x wager plus amount on 12

$5$57 (11 x $5) + ($2 on 2)$11 (2 x $5) + $1 on 3/11$26 (5 x $5) + $1 on 12
$10$114 (11 x $10) + ($4 on 2)$22 (2 x $10) + $2 on 3/11$52 (5 x $10) + $2 on 12
$15$171 (11 x $15) + ($6 on 2)$33 (2 x $15) + $3 on 3/11$78 (5 x $15) + $3 on 12
$20$228 (11 x $20) + ($8 on 2)$44 (2 x $20) + $4 on 3/11$104 (5 x $20) + $4 on 12

Whirl Bets

Whirl bet calculations are a breeze. If the 7 is rolled, it's a push. Otherwise:

Amount Wagered

If Ace-Deuce or 11 is rolled
Formula = 2 x wager + amount on # that was rolled

If 2 or 12 is rolled
Formula = 5 x wager plus amount on # that rolled

$5$11 (2 x $5) + ($1 on 11 or 3)$26 (5 x $5) + $1 on 3
$10$22 (2 x $10) + ($2 on 11 or 3)$52(5 x $10) + $2 on 3
$15$33 (2 x $15) + ($3 on 11 or 3)$78 (5 x $15) + $3 on 3
$20$44 (2 x $20) + ($4 on 11 or 3)$104 (5 x $20) + $4 on 3

Three Way Craps

Don't confuse three way craps with 'Any Craps'. A three way craps wager is made in increments of $3, one dollar each on the 2,12,and 3. It's paid according to the following table:

Three Way Craps

Amount Wagered

If 2 or 12 is rolled
Formula = 9 x wager + amount on # that was rolled

If ace-deuce is rolled
Formula = 4 x wager plus amount on the 3

$3$28 (9 x $3) + ($1 on 2 or 12)$13 (4 x $3) + $1 on 3
$6$56 (9 x $6) + ($2 on 2 or 12)$26 (4 x $6) + $2 on 3
$9$84 (9 x $9) + ($3 on 2 or 12)$39 (4 x $9) + $3 on 3
$12$112 (2 x $12) + (4 on 2 or 12)$52 (4 x $12) + $4 on 3

That covers the basic proposition bets. There are many, MANY, variations of these bets with catchy names. Again, I must emphasize that if you don't understand the payoff, don't make the wager. Good luck!

See You At The Tables,

Soft Touch

PS Review the Books and products listed. I would love to see you at one of our live events!

slackyhacky
I finally thought about my $3 place bets I have so often played at The Freemont.
The house edge on those are way bigger than usual! (Except 6,8 which are the same as if placing $6). 3 pays 4 on 5/9 and 3 pays 5 on 4/10.
So given the tremendous advantage to the casino, why don't more casinos offer such a thing?
Even with such a high house edge, I made a good amount because I am such a phenomenal craps player- perhaps the worlds best behind mustang Sally.
I am what some call a control player. Most control players control the dice. But I control my bets - oh so well. ;)
  1. The 3-Way Craps is similar to the “Any Craps” roll, but it is three separate wagers, while “Any Craps” is a single wager. The 3-Way Craps pays if either the 2, 3, or 12 is paid before the 7 is rolled. The payout for a 2 or a 12 in a Three-Way Craps bet is 30:1, while the payout for an 11 is 15:1.
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DeMango
Here in Biloxi, when there is a $3 game, the 6 & 8 pay even money! Just another tax on the poor!
When a rock is thrown into a pack of dogs, the one that yells the loudest is the one who got hit.
RonC

This straddle indicates a “fractional” bet such that half your bet is an Any Craps bet and the other half is a bet on the 11. If an Any Craps appears (i.e., a 12, 3, or 2), then you win $3.50 because the payoff is 7:1 (i.e., $0.50 multiplied by 7 = $3.50).

I finally thought about my $3 place bets I have so often played at The Freemont.
The house edge on those are way bigger than usual! (Except 6,8 which are the same as if placing $6). 3 pays 4 on 5/9 and 3 pays 5 on 4/10.
So given the tremendous advantage to the casino, why don't more casinos offer such a thing?
Even with such a high house edge, I made a good amount because I am such a phenomenal craps player- perhaps the worlds best behind mustang Sally.
I am what some call a control player. Most control players control the dice. But I control my bets - oh so well. ;)


The 6/8 would pay the same for $5 or $3--even money--anywhere I've played. You are still giving up something in not betting it for $6, which would payout $7...or does the casino pay the fifty cents on a $3 bet?
DJTeddyBear
As discussed yesterday in another thread, the Fremont and a couple other downtown places have half dollars used exclusively for $3 place bets on 6/8.
I invented a few casino games. Info: http://www.DaveMillerGaming.com/ ————————————————————————————————————— Superstitions are silly, childish, irrational rituals, born out of fear of the unknown. But how much does it cost to knock on wood? 😁
slackyhacky

The 6/8 would pay the same for $5 or $3--even money--anywhere I've played. You are still giving up something in not betting it for $6, which would payout $7...or does the casino pay the fifty cents on a $3 bet?


Two pink chips, .25cents each.
Using 25 cent chips allows you to lay 4 and 10 for $10 and buy a $5 4/10.
miplet

I finally thought about my $3 place bets I have so often played at The Freemont.
The house edge on those are way bigger than usual! (Except 6,8 which are the same as if placing $6). 3 pays 4 on 5/9 and 3 pays 5 on 4/10.
So given the tremendous advantage to the casino, why don't more casinos offer such a thing?
Even with such a high house edge, I made a good amount because I am such a phenomenal craps player- perhaps the worlds best behind mustang Sally.
I am what some call a control player. Most control players control the dice. But I control my bets - oh so well. ;)


A player playing $5 place 5 has the same expected loss as a $3 place 5 player. They are equivalent to a $1 put bet with 4x odds and 2x odds respectively. Same thing for the 10.
“Man Babes” #AxelFabulous
slackyhacky

A player playing $5 place 5 has the same expected loss as a $3 place 5 player. They are equivalent to a $1 put bet with 4x odds and 2x odds respectively. Same thing for the 10.


A $3 dollar placed on 5 pays $4. 4/3=1.33333

$3 Craps Las Vegas

A $5 dollar placed on 5 pays $7. 7/5= 1.4
Explain to me how that difference doesn't make expected loss different.
miplet

A $3 dollar placed on 5 pays $4. 4/3=1.33333
A $5 dollar placed on 5 pays $7. 7/5= 1.4
Explain to me how that difference doesn't make expected loss different.


$4*4 - $3*6 = -$2
$7*4 - $5*6 = -$2
Same for The 10:
$5*3 - $3*6 = -$3
$9*3 - $5*6 = -$3
“Man Babes” #AxelFabulous
slackyhacky

$4*4 - $3*6 = -$2
$7*4 - $5*6 = -$2
Same for The 10:
$5*3 - $3*6 = -$3
$9*3 - $5*6 = -$3


I don't understand your math - I mean what each number is suppose to represent.
However, use English - or explain to me like I am 10 years old...
If I risk three dollars, and win four dollars - I make 133% of my original bet.
If I risk five dollars, and win seven dollars - I make 140% of my original bet.
How is that not worse to bet $3 to win $4?3 craps
MathExtremist

I don't understand your math - I mean what each number is suppose to represent.
However, use English - or explain to me like I am 10 years old...
If I risk three dollars, and win four dollars - I make 133% of my original bet.
If I risk five dollars, and win seven dollars - I make 140% of my original bet.
How is that not worse to bet $3 to win $4?


$3 Craps Vegas Strip

He's looking at expected loss in dollars, not as a percentage of the initial wager. Too many people focus on expected loss relative to total wager but your loss in currency is what really matters both to your wallet and to the casino. To that point: a casino's ADT measurement for you is in dollars, not percentages.
If you risk $3 dollars to win $4 2/5 of the time and lose the $3 3/5 of the time, your expected loss is 20c. Out of the $3 initial wager, that 20c represents a 6.67% edge.
If you risk $5 dollars to win $7 2/5 of the time and lose the $5 3/5 of the time, your expected loss is *still* 20c. Out of the $5 initial wager, that 20c represents a 4% edge, which is the normally-reported edge for the place 5 bet.
But importantly, if you make place 5 bets for an hour, your expected loss is the same regardless of whether you bet $3 or $5. The variance is higher if you bet $5 but the mean is the same for both. Craps

$3 Craps Fremont

This is no different than saying that the hourly expected loss for making $10 pass bets with 3/4/5x odds is the same as making $10 pass bets with no odds, which it is.

Craps 3 Point Molly


$3 Craps Casino Royale

Edit: I should add that it's commonly accepted that the pass bet is 'better' than the hardway bets. However, consider that the expected loss per hour for a $10 passline bettor is about $5, while the expected loss per hour for a $1 hardway bettor (any single hardway) is about $3.33. So between the two, who's making the 'better' bet?

Craps 3 4 5 Odds

'In my own case, when it seemed to me after a long illness that death was close at hand, I found no little solace in playing constantly at dice.' -- Girolamo Cardano, 1563